Question

$\lim _{x\to \:3}\left(\frac{5x^2-8x-13}{x^2-5}\right)$

solve

Answer 1

$\lim _{x\to \:3}\left(\frac{5x^2-8x-13}{x^2-5}\right)$

$\rule{250}{6}$

$\lim _{x\to \:3}\left(\frac{5x^2-8x-13}{x^2-5}\right)=2$

$\mathrm{Plug\:in\:the\:value}\:x=3$

$=\frac{5\cdot \:3^2-8\cdot \:3-13}{3^2-5}$

$\mathrm{Simplify\:}\frac{5\cdot \:3^2-8\cdot \:3-13}{3^2-5}:\quad$

$=2$

Answer 2

Answer:

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