Question

$log_{2x + 3}(x + 4) > - 1$
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Answer 1

Answer:

Subscripts and superscripts (such as exponents) can be made using the underscore _ and carat ^ symbols respectively.

Symbol Command Symbol Command

$2^{2}$ 2^2 $\textstyle a_i$ a_i

$\textstyle 2^{23}$ 2^{23} $\textstyle n_{i-1}$ n_{i-1}

$a^{i+1}_3$ a^{i+1}_3 $x^{3^2}$ x^{3^2}

$2^{a_i}$ 2^{a_i} $2^a_i$ 2^a_i

Notice that we can apply both a subscript and a superscript at the same time. For subscripts or superscripts with more than one character, you must surround with curly braces. For example, x^10 produces $x^10$, while x^{10} produces $x^{10}$

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Answer 2

(2x+3)^-1>x+4 as log form
So 1/2x+3>x+4
Or 1>(x+4)(2x+3)
Or 2x^2+11x+12-12x^2+11x+11X< - 11 +_ sq root 33
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