Question

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which has maximum molecules?

(a)7g N2

(b)2g H2

(c)16g NO2

(d)16g O2

Answer 1

2 g hydrogen because it has 2 moles constituting it. so total no. of molecules will be 12.044 x 10²³ ( Na X 2 )

since one mole has avogadro no. of molecules, 2 moles will have twice the avogadro no. of molecles

rest have 3.011 x 10²³ , 2.04 x 10²³ & avogadro no. of molecules resp

Answer 2

Hello GRANDPA MAX!!

→ 1) 7g of N2

1 mole of N2 = 14 ×2=28g

7g of N2 = 7/28 = 1/4 mole

number of molecules in it = 1/4 * Na

where, Na is avagedro constant

1 Na = 6.022*10^23 atoms/molecules/ions

2) 2g H2

→1mole H2 =2g

so, numberof molecules =Na

3) 16 g NO2

→ number of molez = 16/46 * Na

4)16g O2

→ Number of molecules = 16/32 *Na

i.e Na/2

so, maximum number of molecules are present in H2

hope it helps!!

#Jaihind