Physics, asked by Anonymous, 11 months ago

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Q. A biconcave lens of power P vertically splits into two identical plano concave parts. The power of each part will be

(a) 2P

(b) P/2

(c) P

(d) P/√2

Answers

Answered by Anonymous

$\large{\red{\underline{\tt{Given-}}}}$

Power of lens = P

$\large{\red{\underline{\tt{To\:Find-}}}}$

Power of each part

$\large{\red{\underline{\tt{Solution}}}}$

On mutual terms ,

Power is inversely propotional to the focal length.

Also, Power = $\sf\dfrac{1}{Focal\:length}$

Now, Focal length and thickness have a relation.

And the relation turns out be

FOCAL LENGTH is INVERSELY propotional to THICKNESS i.e. f = $\dfrac{1}{t}$

Now, When the lens splits up into two equal parts - The focal length is actually doubled (2f)

And as mentioned above , the power will become half of what it was earlier.

SO THE ANSWER TURNS OUT BE - Option (b)

$\large{\red{\underline{\tt{Answer-P/2}}}}$

$\rule{200}2$

Answered by Anonymous

$\huge \mathbb \fcolorbox{black}{pink}{ANSWER:}$

$\implies b) P/2$

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