Math, asked by EuphoricEpitome, 10 months ago

$<body bgcolor= blue><marquee direction="up"><font color=pink>$
Solve the question.
No spam please..
$<body bgcolor= blue><marquee direction="up">$

Attachments:

Answers

Answered by EkVillen

Answer:

Step-by-step explanation:

x^2 + y^2 + 2z^2 = 4x - 2z + 2yz - 5

=> x^2 + y^2 + z^2 + z^2 = 4x - 2z + 2yz - 5

=> (x^2 - 4x + 4) + (y^2 - 2yz + z^2) + (z^2 + 2z + 1) = 0 , completing the square

=> (x - 2)^2 + (y - z)^2 + (z + 1)^2 = 0

x - 2 = 0

y - z = 0

z + 1 = 0 , since we have a sum of squares

=> (x, y, z) = (2, -1, -1)

Hence,

x - y - z = 4

Ans...

Answered by Anonymous

Answer:

$<body bgcolor= red><marquee direction="up"><font color=white>$

x 2 +y 2 +2z 2 =4x−2z+2yz−5

⟹(x 2 −4x+4)+(y 2 −2yz+z 2 )+(z +2z+1)=0

⟹(x−2) 2 +(y−z) 2 +(z+1) 2 =0

⟹x=2,y=z,z=−1

x−y−z=2+1+1=4

here your answer ✌❤

Previous Question

Next Question