Kripaya attachment solve karein....dhanyawad..
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Explanation:
ΔTF = KF* MOLALITY [ MOLALITY= GIVEN MASS*1000
-------------------------------
MOLAR MASS * MASS OF
SOLVENT]
GIVEN MASS = 0.1 G
MOLAR MASS = 329 G
KF = 1.86
ΔTF = 1.86 * 0.1*1000/329*100
ΔTF = 0.0056 K
Δ TF = - 5.7*10^-3
HOPE THIS HELPS.
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