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NM||KL
60°
P=50°, S=90°
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10. The given figure is a trapezium because it is a quadrilateral whose opposite sides are parallel and all its sides are of unequal length.
NM and KL are parallel.
11. Angle ACD = ABC = 120° (Parallel line properties)
Let angle DAB=BCD= x
120 + 120 + x + x = 360 (Sum of all angles of a quadrilateral = 360°)
2x = 360 - 240
2x = 120
x = 120/2
x = 60
Hence angle C = 60°
12. Angle S = R = 90° (Parallel line properties)
Let angle P be x
90 + 90 + 130 + x = 360 (Sum of all angles of a quadrilateral = 360°)
x = 360 - 310
x = 50
Measurement of angle P = 50°
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