Attachments:
Answers
Answered by
2
vapor density = mol .wt /2
molwt = 29×2=58 g
carbon
62.1/12=5.175
Hydrogen
10.3/1=10.3
Simple ratio
carbon
5.175/5.175=1
Hydrogen
10.3/5.175=1.99=2
Empirical formula =CH2
empirical mass =14
molar mass =58 g
molar mass = n× empirical mass
n=molar mass/empirical mass
n=58/14=4
molecular formula = 4(CH2)=C 4 H8
hence the answer is a
(as there is only one option containing 4 carbons and 8 Hydrogen)
Similar questions