Physics, asked by Anonymous, 10 months ago

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a body of mass 10kg revolves in a circle of diameter 0.40 M making thousand Revolution per minute calculate its linear velocity and centripetal acceleration ​

Answers

Answered by Anonymous
5

Here, m=10 kg, r=0.20m, v=1000/60 s^-1

Angular speed,

w = 2\pi \: v = 2\pi \times  \frac{1000}{60}  =  \frac{100\pi}{3} rad ^{ - 1}

Linear velocity,

v = rw = 0.20 \times  (\frac{100\pi}{3} ) =  \frac{20\pi}{3} ms^{ - 1}

Centripetal acceleration,

a = rw ^{2}  = 0.20 \times (  \frac{100\pi}{3}  )^{2}  =  \frac{2000\pi^{2} }{9} ms^{ - 2}

Answered by azizalasha
1

Answer:

Exsolvedplanation:

v = 10³/60( 0.40π ) = 21 m/s

a = v²/2r = 21²/0.8 = 26m/s²

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