Question

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calculate the temperature of a 4.0 mole of a gas working 5 DM cube at 3.32 bar​

Answer 1

Answer:

Hello mate✌✌✌

Given,

n = 4.0 mole

v = 5 dm^3

p = 3.32 bar

R = 0.083 bar dm3 K^–1 mol^–1

From ideal gas solution,

pV = nRT

pV = nRT⇒ T = pV / nR

pV = nRT⇒ T = pV / nR = (3.32x5) / (4x0.083)

pV = nRT⇒ T = pV / nR = (3.32x5) / (4x0.083) = 50K

pV = nRT⇒ T = pV / nR = (3.32x5) / (4x0.083) = 50KHence, the required temperature is 50 K.

Hope it helps✌✌✌

Answer 2

If gas is assumed to be ideal then

Use ideal gas equation Pv= nRT

T=Pv/(nR)

=3.32×5/4×0.083

= 50k

Temp of gas is 50k

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