Question

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what will be the minimum pressure required to compress 500 DM cube of air at 1 bar to 200 DM cube at 30 degree Celsius ​

Answer 1

Given,

P1=1

P2=?

V1=500 dm^3

V2=200dm^3

Apply Boyle's law P1V1 = P2V2 to calculate P2 as temp remains constant.

P2= P1V1'/V2

=1 bar × 500 dm^3 / 200 dm^3

= 2.5 bar

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Answer 2

Answer:

Hi

Here is your answer,

P₁ = 1 

P₂ = ?

V₁= 500 dm³

V₂= 200 dm³

Apply boyle's law  p₁V₁=p₂V₂ to calculate p₂ as temperature remains constant.

p₂ = p₁V₁/ V₂ = 1 bar × 500 dm³/ 200 dm³ = 2.5 bar

2.5 is the required answer !