Question

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please solve ques 11
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Answer 1

Answer:

12044×(10)^17

Explanation:

aluminium oxide=Al2O3

molecular mass=27*2+16*3=54+48=102u

given mass=0.051g

hence no. of moles, n

$= \frac{0.051}{102} = \frac{51}{102000} = \frac{1}{2000}$

no. of Al2O3 molecules on this much mole(n)

=n×Na (where Na= Avogadro's number)

=

$\frac{1}{2000} \times 6.022 \times {10}^{23}$

$= 6022 \times {10}^{17}$

now, number of Al ions per molecule=2

so no. of Al ions

$= 2 \times 6022 \times {10}^{17}$

$= 12044 \times {10}^{17}$

Answer 2

Hope It Help You.........