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Resistance of platinum wire at ice point (0°C) = 5 Ω
Resistance of platinum wire at steam point (100°C) = 5.5 Ω
The resistance of the platinum wire is = 5. 8 Ω
Now, if we assume :
- R₀ = 5 Ω
- R₁₀₀ = 5. 5 Ω
- R
= 5.8 Ω
As a = R₁₀₀ - R₀ / R₀ x 100 = R - R₀ / R₀ x t
Therefore, R- R₀ / R₁₀₀ - R₀ x 100
= 5.8 - 5 / 5.5 - 5 x 100
= (0.8 / 0.5) x 100
= 160°C
∴ So, he actual temperature at which the resistance of the platinum wire is 5.8 Ω is 160°C.
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Answer:
160°C
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