Math, asked by govindaher1, 5 months ago



(m + 2n) { }^{2}  = m {}^{2}  + ...........   + 4n {}^{2}

Answers

Answered by shruti6687
0

Answer:

If for a sequence (t_{n}), S_{n}= 2n^{2 , find (t_{n}) and show that the sequence is an A.P. ii) If for a sequence (t_{n}), S_{n}=4n^{2 ...

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Answered by Anonymous
10

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(m + 2n)² = (m)² + 2 (m) (2n) + (2n)²

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