Math, asked by Anonymous, 6 hours ago


\mathfrak\purple{Question:-}
Sakshi marks an article up to 50% and allows a discount of 20% and sells it to Priya, who sells it for Rs 20 more than the cost price, which is 30% more than the original cost price. Then the profit percentage of Priya is?

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Answers

Answered by aakansha2424
11

8.33%

Step-by-step explanation:

Let the cost price of Sakshi = Rs.a

Then her marked price = Rs. 1.5 and her

selling price = Rs. 1.5a (0.8) = Rs. 1.2a

Priya's cost price = Rs. 1.2a

Priya's selling price = Rs. (1.2a + 20)

= Rs. 1.3a ⇒ a = 200

So, Priya's cost price = 1.2a = Rs. 1.2 (200) = 240 Priya's profit % = (20/240) x 100% = 8.33%

Hope it helps! :)

Answered by mathdude500
6

\large\underline{\sf{Solution-}}

Given that,

Sakshi marks an article up to 50% and allows a discount of 20% and sells it to Priya, who sells it for Rs 20 more than the cost price, which is 30% more than the original cost price.

Let assume that

Cost Price of an Article be Rs 100

As she maks an article up to 50 %.

It means, Marked Price of Article = 100 + 50 = Rs 150

Now, Discount % = 20%

We know,

 \red{\boxed{\sf{ Selling \: Price =  \frac{(100 - Discount\%) \times Marked \: Price}{100}}}}

So,

\rm :\longmapsto\:Selling \: Price = \dfrac{(100 - 20) \times 150}{100}

\rm :\longmapsto\:Selling \: Price = \dfrac{(80) \times 3}{2}

\bf\implies \:Selling \: Price = Rs \: 120

So,

Selling Price of Sakshi becomes Cost Price of Priya

Now,

Priya sells an article which is 30 % more than the original Cost price.

So, it means

Selling Price of an Article = 100 + 30 = Rs 130

Now, We have

Cost Price of article = Rs 120

Selling Price of article = Rs 130

So, it implies Selling Price > Cost Price

So, it means there is Profit in this transaction

We know

 \red{\rm :\longmapsto\:\boxed{\sf{ Profit = Selling Price - Cost Price}}}

\rm\implies \:Profit = 130 - 120 = \: Rs \: 10

Now, We know that

 \purple{\rm :\longmapsto\:\boxed{\sf{ Profit\% =  \frac{Profit}{Cost \: Price}  \times 100\%}}}

So, on substituting the values, we get

\rm :\longmapsto\:Profit\% = \dfrac{10}{120} \times 100\%

 \\  \red{\rm\implies \:\boxed{ \:  \: \sf{ Profit\% = 8.33 \: \% \:  \: }}} \\

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\begin{gathered}\: \: \: \: \: \: \begin{gathered}\begin{gathered} \footnotesize{\boxed{ \begin{array}{cc} \small\underline{\frak{\pmb{ \red{More \: Formulae}}}} \\ \\ \bigstar \: \bf{Gain = \sf S.P. \: – \: C.P.} \\ \\ \bigstar \:\bf{Loss = \sf C.P. \: – \: S.P.} \\ \\ \bigstar \: \bf{Gain \: \% = \sf \Bigg( \dfrac{Gain}{C.P.} \times 100 \Bigg)\%} \\ \\ \bigstar \: \bf{Loss \: \% = \sf \Bigg( \dfrac{Loss}{C.P.} \times 100 \Bigg )\%} \\ \\ \\ \bigstar \: \bf{S.P. = \sf\dfrac{(100+Gain\%) or(100-Loss\%)}{100} \times C.P.} \\ \: \end{array} }}\end{gathered}\end{gathered}\end{gathered}

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