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tamizhinian22:
n = 125
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(n^1*-5^4)/n^2=5
(n^1*(-5)^4*n^-2)=5
n^1-2*(-5)^4=5^1
n^-1=5^1/(-5)^4
5^1=(25)^(1/2)
(-5)^4=(25)^2
n^-1=25^(1/2)*25^2
n^-1=25^((1/2)+2)
n^-1=25^(3/2)
(1/n) =5^(3/2)*2
n=1/125
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(n^1*(-5)^4*n^-2)=5
n^1-2*(-5)^4=5^1
n^-1=5^1/(-5)^4
5^1=(25)^(1/2)
(-5)^4=(25)^2
n^-1=25^(1/2)*25^2
n^-1=25^((1/2)+2)
n^-1=25^(3/2)
(1/n) =5^(3/2)*2
n=1/125
Please mark as brainliest and follow me if you like the answer.
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