Question

$p(0) = 2 + t + 2t {}^{2} - t {}^{2}$
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Answer 1

$\huge\mathfrak\orange{∆nswer!}$

$\large\bold{Given:}$

$\bold{p(0)=2+t+2t^2-t^2}$

$\bold{=>p(0)=2+0+2(0)^2-(0)^2}$

$\bold{=>p(0)=2+0-0}$

$\bold{=>p(0)=2}$

$\huge\bold\purple{p(0)=2}$

$\huge\bold\blue{Hope \ this \ helps...}$

$\huge\bold\green{Brainliest \ Please!}$

$\huge\bold\red{★★★★★★★★★★}$