Question

$p(y) = {y}^{2} - y + 1$
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Answer 1

$<I>$☞Heya Mate ☜

★ ANSWER ...

→ p(y) = y² + 1

→ p(0) = 0² + 1

→ p(0) = 1

❣️hope it helps uh ❣️

Answer 2

HERE IS YOUR NASWER MATE.....

...HERE IS YOU ANSWER MATE....

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