English, asked by ina4kay, 6 months ago

\pi \neq \sqrt{x} \alpha \pi \sqrt[n]{x}

Answers

Answered by jatinraghav123
0

\sqrt[n]{x} \pi \lim_{n \to. 2 ... vidyalaya , gurgaon \lim_{n \to \infty} a_n \lim_{n \to \infty} a_n \neq \pi \sqrt{x} 1.

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