Question

$please \: \: \: answer \: \: \: this -$
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Answer 1

$\huge \fbox \pink{Answer:}$

$\textbf{Given:- } \: \tan∅ = \frac{a}{x}$

$\textbf{To Find :- } \text{The Value} \: \frac{x}{ {a}^{2} + {x}^{2} }$

$\sf \colorbox{pink} {Solution:} \: \tan ∅ = \frac{a}{x}$

$\textbf{We Know that} \: \tan∅ = \frac{ \sin \: a }{ \cos \: a }$

$\textbf{So} \: a = \sin∅ ,x = \cos∅$

$\textbf{At the Value}$

$⇒ \frac{x}{ {a}^{2} + {x}^{2} } = \frac{x}{ {\sin}^{2} ∅ + { \cos }^{2} ∅}$

$= \frac{ \cos}{ \sqrt{1} }$

$= \cos∅$

$\textbf{Hence The Value of} \: \cos∅$

$\sf \colorbox{gold} {\red(ANSWER ᵇʸ ⁿᵃʷᵃᵇ⁰⁰⁰⁸}$

Answer 2

tan∅=

x

a

\textbf{We Know that} \: \tan∅ = \frac{ \sin \: a }{ \cos \: a }We Know thattan∅=

cosa

sina

\textbf{So} \: a = \sin∅ ,x = \cos∅Soa=sin∅,x=cos∅

\textbf{At the Value}At the Value

⇒ \frac{x}{ {a}^{2} + {x}^{2} } = \frac{x}{ {\sin}^{2} ∅ + { \cos }^{2} ∅}⇒ a 2 +x 2

x = sin 2

∅+cos 2 ∅x

= \frac{ \cos}{ \sqrt{1} }= 1

cco= \cos∅=cos∅