Question

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Answer 1

Hêy Fríèñd..

Here is the Solution..

Solved Using The Splitting The Middle Term Method

ii) a² - 16a - 80

= a² - (20a-4a) - 80

= a² - 20a + 4a - 80

= a(a - 20) + 4(a -20)

= (a - 20)(a + 4)

Let (a - 20) = 0 . & (a + 4) = 0

Thus, a = 20 or a = -4

iii) a²y³ - 2aby² + b²y

= y (a²y - 2aby + b²)

= y {a²y - (aby + aby) + b²}

= y (a²y - aby - aby +b²)

= y [ay(a - b) - b(ay - b)]

= y {(ay - b)(ay - b)}

= y(ay - b)(ay - b)

Let y(ay - b) =0 & y(ay - b)=0

Thus, y = b/a or y = b/a

13) 4y² - 12y + 9

= 4y² - (6y + 6y) + 9

= 4y² - 6y - 6y + 9

= 2y(2y - 3) - 3(2y - 3)

= (2y - 3)(2y - 3)

= (2y - 3)²

Let, (2y - 3)² = 0

Thus , y = 3/2

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I Hope This Will Help You◉‿◉

~ ♥️☺️Thnx ~

@QwertyPs