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let us assume that ✓3 is a rational number such that ✓3= p/q where p and q are positive integers and hcf(p,q)=1
=> ✓3 = p/q
=> (✓3)^2 = p^2/q^2 ( squaring both
sides)
=> 3 = p^2/q^2
=> q^2 = p^2/3
since, p^2 is divisible by 3
therefore, p is also divisible 3
therefore, p = 3r
=> q^2 = (3r)^2/3
=> q^2 = 9r^2/3
=> q^2 = 3r^2
=> 3r^2 = q^2
=> r^2 = q^2/3
since, q^2 is divisible by 3
therefore, q is also divisible 3
therefore, p and q both have 3 as their common factor.
but contradicts the fact that p and q have no common factor other than 1 ..
so, out assumption is wrong
therefore, ✓3 is an irrational number..
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