Question

$prove \: that \frac{ \sin \: a - 2 { \sin }^{3} \: a }{2 { \cos }^{3} a - \cos \: a } = \tan \: a$
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Answer 1

LHS

(SinA - sin^3A)/(2vos^3A - cosA)

SinA ( 1 - 2sin^2A)/cosA(2cos^2A - 1)

tanA {cos2A/cos2A)

tanA

formula used

cos2A = 2cos^2A - 1 = 1 -2sin^2A

Answer 2

Hope this might help u!!

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