Question

$prove \: that \: \frac{sin \: theta \: - \: cos \: theta \: }{sin \: theta \: + \: cos \: theta} = \frac{1 - \: \cot \: theta \: }{1 + cot \: theta}$
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Answer 1

Answer:

let theta be x

Step-by-step explanation:

$\frac{sinx - cosx}{sinx + cosx} \\ = \frac{sinx(1 - \frac{cosx}{sinx}) }{sinx(1 + \frac{cosx}{sinx} )} \\ = \frac{1 - cotx}{1 + cotx} \\ hence \: proved$

Answer 2

Answer:

this is correct.......................