Question

$prove \: yourself \: brainlians$
In ∆ABC, if angle C=90°, prove that sin²A+sin²B=1.​

Answer 1

sin A = BC/AB

sin B = AC/AB

sin^2 A + sin^ 2 B. = BC^2/AB^2 + AC^2/AB^2

= BC^2 + AC^2)/ AB^2

AS its right angled

AB^2 = AC^2 + BC^2

So it becomes AB^2/ AB^2 = 1

Answer 2

Thinks it would have helped