Math, asked by xfxfjtushsrruaary, 4 months ago

q(y) = 27y - 4y + \sqrt{11 \: } \: at \: y = 3

Answers

Answered by Anonymous
0

 \huge \underline {{  \green  {\mathbb{QUESTION}}}}

 \LARGE\tt \orange {q(y) = 27y - 4y + \sqrt{11 \: } \: at \: y = 3}

 \huge \underline { {\blue  {\mathbb{ANSWER}}}}

 \large\pink {\implies \tt \: q(y) \:  =  \: 27y \:  - 4y \:  +  \sqrt{11} }

 \Large\purple {  \sf   Put \:  y   =   3}

 \large\pink{ \to \tt \:  q(3) \:  = 27(3) - 4(3) +  \sqrt{11} }

 \large\pink{ \tt \to \: q(3) = 69 \:  + 3.31  \: (  \because\sqrt{11} \approx \: 3.31)}

 \Large\red {\to \tt \: q(3) = 72.31}

 \huge{ \green{\boxed{\underline{☆тɦαɳҡร☆}}}}

Answered by MissLuxuRiant
1

\huge \underline { {\blue {\mathbb{ANSWER}}}}

\large\pink {\implies \tt \: q(y) \: = \: 27y \: - 4y \: + \sqrt{11}

\Large\purple { \sf Put \: y = 3}

\large\pink{ \to \tt \: q(3) \: = 27(3) - 4(3) + \sqrt{11}

\large\pink{ \tt \to \: q(3) = 69 \: + 3.31 \: ( \because\sqrt{11} \approx \: 3.31)}

\Large\red {\to \tt \: q(3) = 72.31}

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