Question

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Q)1. A thin wire 20 cm long is formed into a rectangle. If the width of this rectangle is 4 cm, what is its length?

Q)2. A square carromboard has a perimeter of 320 cm. How much is its area?
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Answer 1

1)

Given :-

A thin wire 20 cm long is formed into a rectangle. If the width of this rectangle is 4 cm

To Find :-

Length

Solution :-

We know that

Perimeter of rectangle = 2(l + b)

Let the length of wire be l

⇒ 20 = 2(l + 4)

⇒ 20/2 = l + 4

⇒ 10 = l + 4

⇒ 10 - 4 = l

⇒ 6 - l

Hence, Length of wire is 6 cm

2)

Given :-

A square carrom board has a perimeter of 320 cm

To Find :-

Area

Solution :-

We know that

Side of square = Perimeter/4

⇒ Side = 320/4

⇒ Side = 80 cm

Now

Area = (side)²

⇒ Area = (80)²

⇒ Area = 6400 cm²

Answer 2

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1) A thin wire 20 cm long is formed into a rectangle. If the width of this rectangle is 4 cm, what is its length?

${{{{{{{{{Answer}}}}}}}}}$

Perimeter = 20 cm

Width = 4 cm

We know, perimeter = 2(length + breadth)

Hence, 2 (length + breadth) = 20

Or, length + 4 = 20÷2 = 10

Or, length = 10 – 4 = 6 cm

${{{{{{{{{Question}}}}}}}}}$

A square carromboard has a perimeter of 320 cm. How much is its area?

${{{{{{{{{Answer}}}}}}}}}$

Perimeter = 320 cm

We know, perimeter = 4 x Side Hence, 4 x Side = 320 cm Or, Side = 320 4 = 80 cm

Now, area = Side x Side

= 80 x 80 = 6400 square cm

Thank you