Question

$\red{\bold{\underline{\underline{❥Question᎓}}}}$4x-5y+16=0 and 2x+y-6=0

Answer 1

$\huge \tt{Answer}$

$\tt{✯ \: 4x - 5y + 16 = 0 \: \: \: \: -(i)}$

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$\tt{✯ \: 2x+y-6=0 \: \: \: \: -(ii)}$

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$\red{\sf From \: (i)}$

$\tt{x = \frac{-16 + 5y}{4}}$

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$\red{\sf Put \: this \: value \: of \: x \: in \: (ii)}$

$\tt{2( \frac{-16 + 5y}{4} ) + y - 6 = 0}$

$\tt{\frac{-32 + 10y}{4} + y - 6 = 0}$

$\tt{-32 + 10y + 4y - 24 = 0}$

$\tt{14y - 56 = 0}$

$\tt{14y = 56}$

$\tt{y = \frac{56}{14}}$

$\boxed{\tt{y = 4}}$

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$\red{\sf Put \: value \: of \: y \: in \: (i)}$

$\tt{4x - 5y + 16 = 0}$

$\tt{4x - 5(4) + 16 = 0}$

$\tt{4x - 20 + 16 = 0}$

$\tt{4x - 4 = 0}$

$\tt{4x = 4}$

$\tt{x = \frac{\cancel{4}}{\cancel{4}}}$

$\boxed{\tt{x = 1}}$

$\red{\sf Therefore, \: value \: of \: x = 1 \: and \: y = 4}$

Answer 2

$\huge{\bold☘}\mathfrak\pink{\bold{\underline{{ ℘ɧεŋσɱεŋศɭ}}}}{\bold☘}$

$\huge\tt\red{\bold{\underline{\underline{❥Question᎓}}}}$$\huge\tt{4x-5y+16=0}$ $\huge\tt{and}$$\huge\tt{ 2x+y-6=0}$

$\huge\tt{\boxed{\overbrace{\underbrace{\blue{Answer</p><p> }}}}}$

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$\huge\tt⇛4x - 5y + 16 = 0$

$\huge\tt⇛2x + y - 6 = 0$

$\huge\tt⇛2x = 6 - y$

$\huge\tt{\red{x = \frac{6 - y}{2}}....(1)}$

Now , Substitute Value Of X In First Equation To Find Out The Value Of Y

$\huge\tt⇛4x - 5y + 16 = 0$

$\huge\tt⇛4 (\frac{6 - y}{2} ) - 5y + 16 = 0$

$\huge\tt⇛\frac{24 - 4y}{2} - 5y + 16 = 0$

$\huge\tt ⇛\frac{24 - 4y - 10y + 32}{2} = 0$

$\huge\tt⇛24 - 14y + 32 = 0$

$\huge\tt⇛56 - 14y = 0$

$\huge\tt⇛- 14y = - 56$

$\huge\tt\mathbb{\boxed{\blue{y = 4}}}$

Now,put the value of $\mathbb{\blue{y}}$ in equation (1)

$\huge\tt{x = \frac{6 - y}{2} = \frac{6 - 4}{2} = \frac{2}{2} = 1}$

$\huge\tt{\red{\boxed{x = 1}}}$

$\huge\tt{∴}$$\huge\tt{X=1 }$$\huge\tt{and}$$\huge\tt{Y=4}$

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