Question

$\red{Question}$

A DNA model was built using the scale 2 cm: 0.0000001 mm. If the model of the DNA chain is 17 cm long, what is the length of the actual chain?

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Answer 1

Step-by-step explanation:

Let x cm be the length o python

ACQ,

60% of x=558

⇒

100

60

×x=558

⇒x=

60

558×100

⇒x=930

(b) We have,

length

mass1

=

length1

mass2

∴

2

24

=

3

mass2

⇒mass2=

2

24×3

=36kg

(c) Length of actual chain 0.000001 mm is measured as 2 cm in the model.

Hence, length of actual chain when length of chain is 17 cm in the model

=

2

0.0000001

×17

=0.00000085mm

Answer 2

SOLUTION

Let the length of the actual chain be x mm. Therefore,

-Ary114

$SOLUTION</p><p> \\</p><p></p><p></p><p>Let \: the \: length \: of \: the \: actual \\ chain \: be \: x \: mm.$

$\\ Therefore, \\ \frac{2}{0.0000001}  cm \\ \\ mm= \frac{17cm}{xmm} \\ \\ </p><p></p><p></p><p>[tex]</p><p>[tex]⇒x= \frac{17 \times 0.0000001}{2} \\ =8.5×0.0000001 \\ =0.00000085 mm$

hope it will help you