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Hey !!!
sec2A = ??
We know that cos2A = cos²A - sin²A
and secA is just reciprocal of cosA
hence sec2A = 1/cos2A
= 1/cos²A - sin²A
= 1/1/sec²A - 1/cosec²A
= 1 /cosec²A - sec²A/sec²A × cosec²A
= cosec²A×sec²A/cosec²A - sec²A Answer
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Hope it helps you !!l
@Rajukumar111
sec2A = ??
We know that cos2A = cos²A - sin²A
and secA is just reciprocal of cosA
hence sec2A = 1/cos2A
= 1/cos²A - sin²A
= 1/1/sec²A - 1/cosec²A
= 1 /cosec²A - sec²A/sec²A × cosec²A
= cosec²A×sec²A/cosec²A - sec²A Answer
******************************
Hope it helps you !!l
@Rajukumar111
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