Math, asked by imuniqueuttamp7vllw, 1 year ago


 \sec(2a)

Answers

Answered by TheLifeRacer
1
Hey !!!

sec2A = ??

We know that cos2A = cos²A - sin²A

and secA is just reciprocal of cosA

hence sec2A = 1/cos2A

= 1/cos²A - sin²A

= 1/1/sec²A - 1/cosec²A

= 1 /cosec²A - sec²A/sec²A × cosec²A

= cosec²A×sec²A/cosec²A - sec²A Answer



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Hope it helps you !!l

@Rajukumar111
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