Question

$sec0 + tan0 = cos0 \div 1 - sin0$
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Answer 1

Step-by-step explanation:

secA+tanA

1/cosA+sinA/cosA

1+sinA/cosA

rationalize with 1-sinA

(1+sinA)*(1-sinA)/cosA*(1-sinA)

1-sin²A/cosA (1-sinA)

cos²A/cosA (1-sinA)

cosA/1-sinA