Question

$\sf\:Coefficient\:of\: x^8 \: y^9\:z^9\: in \\ \sf\:(x + y + z)^{25}$​

Answer 1

Answer : 0

Explanation :

Any term of the expansion

(x+y+z)^n will be in the form

$\sf \: cx^{p}y^{q}z^{r}$

Such that, p + q + r = n

Here,

We are given (x+y+z)^25

So if at all, a term exists then, sum of powers should be equal to 25

Here, Asked to find co efficient of $\sf \: x^8 \: y^9\:z^9\: \:$

Sum of powers = 8 + 9 + 9 = 26

So since the sum of powers didn't equal 25, There will be no such term

Hence coefficient of such term is 0

Answer 2

Answer:

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