Find the ratio of energies of 2nd and 3rd orbit of He+ and Li2+ respectively.
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1
Answer:
1:1
Explanation:
Listen E=-kz^2 ÷n^2
For finding ratio we just have to devide, the respective atomic and orbit number asked and use the above formula we get :(z1÷z2) ^2 ÷(n1÷n2) ^2
(2÷3)^2 ×(3÷2) ^2
Therefore answer is 1:1
IF you like my answer then please brainliest it :)
Aadilaahnazim08:
sorry to say this is not the answer.
oh sorry :(
pls give me the answer in ratio
2÷3
no the correct answer is 1:1 give me the explanations
give me 2 minutes!
got it... I made a silly mistake... check my final answer.. and if you like it then brainliest it :)
thanks
my pleasure :)
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