Question

$\sf{find \: the \: gravitational \: force \: between \: } \\ \sf{a \: man \: of \: mass \: 50kg \: and \: car \: of \: } \\ \sf{mass \: 1500kg \: separated \: by \: 10 \: m.}$
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Answer 1

$\fbox { \sf \huge \underline{solution }} \hookrightarrow \huge$

$\sf \underline{data} \hookrightarrow$

$\sf{⇒m_1 = 50 \: kg,}$

$\sf{⇒m_2 = 1500 \: kg,}$

$\sf{⇒r = 10 \: m,}$

$\sf{⇒g = 6.67 \times 10 { }^{ - 11 \: } n.m {}^{2} {}^{1} / {}_{}kg ,}$

$\sf \underline{to \: find} \hookrightarrow$

$\sf{the \: gravitational \: force \: between \: the \: mn \: and \: the \: car \: } \\ \\ \sf{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: f = \: ? }$

$\sf \underline{answer} \hookrightarrow$

$\sf{⇒f = \frac{gm_1m_2}{r {}^{2} } }$

$\sf{ \frac{ ⇒= 6.67 \times 10 {}^{ - 11} n.m{}^{2} / {}_{ {}^{} } kg\times 50 \: kg \times 1500 \: kg}{ (10m) {}^{2} }}$

$\sf{⇒ = 5.0025 \: \times 10 {}^{ - 8} n}$

$\sf \bold{the \: gravitational \: force \: between \: the \: man \: and \: the \: car = \:} \\ \\ \fbox{\sf \huge{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 5.0025 \times 10 {}^{ - 8} n. \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }}$

Answer 2

The gravitational force on Earth is equal to the force the Earth exerts on you. At rest, on or near the surface of the Earth, the gravitational force equals your weight.