Question

$\sf\huge\underline\red{Question:-}$
$\sf\dashrightarrow \frac{1}{x - 2} + \frac{1}{x - 2} + \frac{1}{x - 4} = 0$
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Answer 1

Answer:

x = 6

x = 3

Step-by-step explanation:

1/x-2 + 1/x-2 + 1/x-4 = 0

2/x-2 + 1/x-4 = 0

2x - 8 + x-2/(x-2)(x-4) = 0

(x-2)(x-4) = 2x + x - 10

x^2 - 4x - 2x + 8 = 3x - 10

x^2 - 9x + 18 = 0

x^2 - 3x - 6x + 18 = 0

x (x - 3) -6 (x - 3) = 0

Therefore, factors are (x-6); (x-3)

x-6 => x=6

x-3 => x=3

Answer 2

Answer:

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Step-by-step explanation:

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