Question

$\sf If \: { \tan }^{2} Θ = 1 - {a}^{2}$
,prove that secΘ +tan3Θ=(2-a2)3/2​

Answer 1

$\huge{\underline{\bf{\purple{Question:-}}}}$

✪ If tan² Θ=1-a², Prove that secΘ+ tan³Θ cosecΘ=(2-a²)³/².

Answer 2

$\huge{\red{\tt Refer \: the \: attachment \: given \: above}}$

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