Question

$\sf{kindly \: solve \: it}$
​

Answer 1

Answer:

$\left[\begin{array}{ccc}-23&3\\17&6\\\end{array}\right]$

Step-by-step explanation:

$A=\left[\begin{array}{ccc}2&1\\0&-2\\\end{array}\right] \\\\B=\left[\begin{array}{ccc}4&1\\-3&-2\\\end{array}\right] \\\\C=\left[\begin{array}{ccc}-3&2\\-1&4\\\end{array}\right]$

$A^{2} +AC-5B$

$A^{2} =\left[\begin{array}{ccc}2&1\\0&-2\\\end{array}\right] \left[\begin{array}{ccc}2&1\\0&-2\\\end{array}\right] \\\\A^{2} =\left[\begin{array}{ccc}4&0\\0&4\\\end{array}\right]$

$AC=\left[\begin{array}{ccc}2&1\\0&-2\\\end{array}\right] \left[\begin{array}{ccc}-3&2\\-1&4\\\end{array}\right] \\\\AC=\left[\begin{array}{ccc}-7&8\\2&-8\\\end{array}\right]$

$5B=5\left[\begin{array}{ccc}4&1\\-3&-2\\\end{array}\right] \\\\5B=\left[\begin{array}{ccc}20&5\\-15&-10\\\end{array}\right]$

$A^{2} +AC-5B$

$\left[\begin{array}{ccc}4&0\\0&4\\\end{array}\right] +\left[\begin{array}{ccc}-7&8\\2&-8\\\end{array}\right] -\left[\begin{array}{ccc}20&5\\-15&-10\\\end{array}\right] \\\\\\\left[\begin{array}{ccc}-3&8\\2&-4\\\end{array}\right] -\left[\begin{array}{ccc}20&5\\-15&-10\\\end{array}\right] \\\\\\\left[\begin{array}{ccc}-23&3\\17&6\\\end{array}\right]$