How do you find experimentally the refrective index of material of prism
Answers
Answer:
hope u got it
Explanation:
Take a prism and place it on the white chart in such a way that the triangular base of the prism is on the chart.
Draw a line around the prism using a pencil. Remove the prism.
It is a triangle. Name its vertices P, Q and R.
Find the angle between PQ and PR. This is the angle of the prism (A).
Mark M on the side of triangle PQ and also draw a perpendicular to the PQ at M.
Place the center of the protractor at M and along the normal mark an angle of 30° and then draw line up to M.
This angle is angle of incidence and note it in a table.
Place the prism in its position again.
Now fix two pins vertically on the line at point A and B.
Look for the images of pins through the prism from the other side and fix another two pins at points C and D in such a way that all the four pins appear to lie along same straight line.
Now remove the prism and take out pins.
Draw a line joining the two pin-holes formed by the pins to meet surface PR.
The angle between the normal at N and the emergent ray is the angle of emergence.
Join M and N. A,B,M,N, C, D represent the path of light.
Extend both incident, emergent rays tell they meet at a point ‘O’.
The angle between these two rays is angle of deviation denoted by ‘D’.
Do the same for various angles of incidence such as 40°, 50° etc.
If we take angle of incidence along x-axis and the angle of deviation along y-axis we get the graph as shown in figure.
The refractive index of prism n = Sin [(A + D)/2] / sin A/2
Answer:
The angle between these two rays is angle of deviation denoted by 'D'. Do the same for various angles of incidence such as 40°, 50° etc. If we take angle of incidence along x-axis and the angle of deviation along y-axis we get the graph as shown in figure. The refractive index of prism μ=sin2Asin[2(A+D)]
^_^^_^^_^^_^^_^