Physics, asked by SweetLily, 1 month ago

 \sf{The \: equation \: \bigg[P+\frac{a}{v²}\bigg](V-b) = constant.}
 \sf{The \: units \: of \: a \: is - }
a) Dyne×cm⁵
b) Dyne ×cm⁴
c) Dyne/cm³
d) Dyne/cm²​

Answers

Answered by Nihar1729
3

Answer:

b) Dyne ×cm⁴ is your answer .

  • Dimension of P = dimension of a/v²  
  • Dyne/cm² = dimension of a /(cm³)²
  •  
  • Dimension of a = Dyne * cm³ * cm³ /cm²
  •  
  • Dimension of a = Dyne * cm⁴

Answered by gshanahmad8
0

Answer:

Answer:

b) Dyne ×cm⁴ is your answer .

Dimension of P = dimension of a/v²  

Dyne/cm² = dimension of a /(cm³)²

 

Dimension of a = Dyne * cm³ * cm³ /cm²

 

Dimension of a = Dyne * cm⁴

Hope it helps you mark me as brainliest

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