Question

$simplify \: \\ (a + b)(2a - 3b + c) - (2a - 3b)c$
it hard but it easy ​

Answer 1

Answer:

$\small\mathtt{ =2a^2-3b^2-bc+ac }$

Step-by-step explanation:

We have

$\small\mathtt{ =(a + b)(2a - 3b + c) = a(2a - 3b+c ) +b (2a-3b+c) }$

$\small\mathtt{ ==2a^2-3ab+ac+2ab-3b^2+bc }$

$\small\mathtt{ =2a^2-ab-3b^2+bc }$

(note, -3ab and 2ab are like term ) And,

$\small\mathtt{ (2a -3b)c=2ac-3bc}$

therefore,

$\small\mathtt{ (a+b)(2a-3b+c)-(2a-3b) c}$

$\small\mathtt{ =2a^ab-3b^2-bc+ac -(2ac-3bc) }$

$\small\mathtt{ =2a^2-ab-3b^2-bc+ac-2ac+3bc }$

$\small\mathtt{ =2a^2-ab-3b^2+(bc+3bc)+(ac-2ac) }$

ans. $\small\mathtt{ =2a^2-3b^2+4bc+ac }$

✌ᴍᴀᴛʜsᴀʀʏᴀʙʜᴀᴛᴛA✌

Answer 2

Hope you will understand the answer