Question

$simplify = \frac{72}{121} {x3y5 \times \frac{77}{108 {x 3y4}^{?} }^{2} } }^{?}$
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Answer 1

Answer:

$simplify : \\ \frac{72 {x}^{3} {y}^{5} }{121} \times (\frac{77}{108 { {x}^{3} {y}^{4} } })^{2} \\ = \frac{72 {x}^{3} {y}^{5} }{121} \times \frac{77}{108 { {x}^{6} {y}^{8} } } \\ = \frac{2}{11} \times \frac{7}{3 {x}^{3 } {y}^{3} } \\ = \frac{14}{33 {x}^{3} {y}^{3} } </p><p>$