Question

${sin}^{2} 90 degree + sin \: 0 \: degree - {sin}^{2} 45 \: degree \times {cos}^{2}45 \: degree$
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Answer 1

Answer:

$\frac{3}{4}$

Explanation:

${ \sin(90) }^{2} + \sin(0) - ( { \sin(45) }^{2} \times { \cos(45) }^{2} ) \\ = {1}^{2} + 0 - ( \: ( { \frac{1}{ \sqrt{2} } )}^{2} \times ( { \frac{1}{ \sqrt{2} }) }^{2} ) = 1 - ( \frac{1}{2} \times \frac{1}{2)} \\ = 1 - \frac{1}{4} = \frac{3}{4}$