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Sin(90 + theta) = Cos (theta)
hope it helps...
hope it helps...
Answered by
1
Hey
→ sin ( A + B ) = sin A cos B + sin B cos A
Note : sin( - A ) = - sin A [ this can be very helful ]
→ sin ( 90° + θ ) = sin90° cosθ + cos 90° sinθ
=> sin ( 90° + θ ) = cos θ + 0 = cos θ
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Another way to arrive at this :
→ cos ( -θ ) = cos θ
Use : sin( 90° - x ) = cos x
=> sin ( 90° - ( -θ ) ) = cosθ
=> sin ( 90° + θ ) = cos θ
→ sin ( A + B ) = sin A cos B + sin B cos A
Note : sin( - A ) = - sin A [ this can be very helful ]
→ sin ( 90° + θ ) = sin90° cosθ + cos 90° sinθ
=> sin ( 90° + θ ) = cos θ + 0 = cos θ
__________________________________________________
Another way to arrive at this :
→ cos ( -θ ) = cos θ
Use : sin( 90° - x ) = cos x
=> sin ( 90° - ( -θ ) ) = cosθ
=> sin ( 90° + θ ) = cos θ
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