Question

$sin \alpha = 3 \div 5where\pi \div 2 \leqslant \alpha \leqslant \pi \: evaluate \: \cos(3 \alpha \: and2 \alpha \)$
​

Answer 1

Step-by-step explanation:

If `cos3theta=cos3alpha,` then the value of `sintheta` can be given by `+-sinalpha` (b) `sin(pi/3+-alpha)` `sin((2pi)/3+alpha)` (d) `sin((2pi)/3-alpha)`