Question

$\sin( \alpha ) \cot( \alpha )$
how much
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Answer 1

Step-by-step explanation:

• (Sin alpha + Cos alpha) . (Tan alpha + Cot alpha)

• (Sin alpha + Cos alpha) . [sin alpha / cos alpha + Cos alpha / Sin alpha ]

• (Sin alpha + Cos apha). [ (Sin² alpha + Cos² alpha) / Sin alpha × Cos alpha ]

• (Sin alpha + Cos alpha) .[ 1 / Sin alpha × Cos alpha ]

• [ Sin alpha / sin alpha × Cos alpha ] + [ Cos alpha / Sin alpha × Cos alpha ]

❤❤❤❤OR❤❤❤❤

• 1 + Cot² alpha = Cosec² alpha
• Sin² alpha = 1 / Cosec² alpha
• Sin² alpha = 1 / Cosec alpha
• Sin² alpha = 1 / √1 + cot² alpha