Question

$\sin(?)$
​

Answer 1

Answer:

nth term of an A.P (an) = pn + q

To find: Common Difference (d)

Proof: We know that,

an = a + (n – 1)d

⇒ pn + q = a + (n – 1)d [given]

⇒ pn + q – a = (n – 1)d sin