Question

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A sum of rupee 2000 is in the form of denominations of rupee 50 and rupee 10 notes. If the total number of notes is 80. Find the number of notes of each type.

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Answer 1

$\huge{\mathfrak\red{Answer}}$

Let us assume ¥10 be 'X'

Let us assume ¥20 be 'Y'

$\huge\red.°. X+Y=50-(1)$

$</p><p>\huge\blue.°. 10x+120y =800$

$\huge\pink{.°. X+2y = {80-(2)}}$

By, Subtracting Equation 1 and Equation 2

$\huge \: Y=30$

$\huge \: X=20$

.°. 20 notes of 10 Rs

.°. 30 notes of 20 Rs.

Khadijah21

Answer 2

Answer

Let the number of 5 rupee notes be x,then

The number of 10 rupee notes =90−x

Then ,according to the question

5x+10(90−x)=500

5x+900−10x=500

5x=400

x=80

There are 80 notes of Rs.5 and 10 notes of Rs.10.