Question

$solve \: {4}^{x + 1} + {4}^{1 - x}$
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Answer 1

Step-by-step explanation:

${4}^{x + 1} + {4}^{1 - x}$

${4}^{x} .4 + 4. {4}^{ - x} \\ 4( {4}^{x} + \frac{1}{ {4}^{x} }) \\ \frac{4}{ {4}^{x} } ( {4}^{2x} + 1)$