Question

$solve$


with explain



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Answer 1

ln(dy/dx) + y = x

ln(dy/dx) = x-y

dy/dx = e^(x-y)

dy/dx = e^x / e^y

dy * e^y = dx* e^x

integrating on both sides we get

e^y +k = e^x + k'

k and k' are constants

e^x - e^y = k-k' = c

c is another constant

e^x - e^y = c

answer is c