Math, asked by Anonymous, 9 months ago

\sqrt{-1} 2^3 \sum \pi ...
and it was delicious!

Answers

Answered by TakenName
1

\sqrt{-1} =i

2^3=8

\sum as 'sum'

\pi as 'pi'

'i eight sum pi' and it was delicious!

i into I

eight into ate

sum into some

pi into pie

Answer : I ate some pie... and it was delicious!

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